23 hours ago
my attempt to do the exercises in sicp.
Friday, July 4, 2008
sicp exercise 1.45
; Exercise 1.45. We saw in section 1.3.3 that attempting to compute square roots by naively finding a
; fixed point of y -> x/y does not converge, and that this can be fixed by average damping. The same
; method works for finding cube roots as fixed points of the average-damped y -> x/y^2. Unfortunately,
; the process does not work for fourth roots -- a single average damp is not enough to make a fixed-point
; search for y -> x/y^3 converge. On the other hand, if we average damp twice (i.e., use the average damp
; of the average damp of y -> x/y^3) the fixed-point search does converge. Do some experiments to
; determine how many average damps are required to compute nth roots as a fixed-point search based upon
; repeated average damping of y -> x/y^(n-1). Use this to implement a simple procedure for computing nth
; roots using fixed-point, average-damp, and the repeated procedure of exercise 1.43. Assume that any
; arithmetic operations you need are available as primitives.
(define tolerance 0.00001)
(define (fixed-point f first-guess)
(define (close-enough? v1 v2)
(< (abs (- v1 v2)) tolerance))
(define (try guess)
(display guess)(newline)
(let ((next (f guess)))
(if (close-enough? guess next)
next
(try next))))
(try first-guess))
(define (average x y) (/ (+ x y) 2))
(define (compose f g)
(lambda(x)
(f (g x))))
(define (repeated f n)
(define (iter i res)
(if (>= i n)
res
(iter (+ i 1) (compose f res))))
(iter 1 f))
(define (square x) (* x x))
(define (fast-exp-iter base exp)
(define (func n b res)
(cond ((= n 0) res)
((even? n) (func (/ n 2) (square b) res))
(else (func (- n 1) b (* res b)))))
(func exp base 1))
(define (average-damp f)
(lambda(x)
(average x (f x))))
(define (func x n)
(lambda(y)
(/ x (fast-exp-iter y (- n 1)))))
; nth root is the fixed-point of the function func
(define (nth-root x n)
(fixed-point (repeated (average-damp (func x n)) 5) 3.0))
(display (nth-root 256 8))(newline)
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